+0

# Can someone whos not a guest answer and explain this geometry?

+2
231
1
+222

Let PQRS be a square with side length 10. The points X and Y lie outside the square such that XQ = 6, XP = 8, YS = 6, and YR = 8. Find XY^2.

May 15, 2020

#1
+25750
+2

Let PQRS be a square with side length 10.
The points X and Y lie outside the square such that XQ = 6, XP = 8, YS = 6, and YR = 8.
Find $$XY^2$$.

$$\begin{array}{|rcll|} \hline XY^2 &=& (6+8)^2 + (6+8)^2 \\ XY^2 &=& 2(6+8)^2 \\ XY^2 &=& 2(14)^2 \\ \mathbf{XY^2} &=& \mathbf{392} \\ \hline \end{array}$$

May 15, 2020