The graph of the equation $y =ax^2 + bx + c$, where $a$, $b$, and $c$ are constants, is a parabola with axis of symmetry $x = -3.$ Find $\frac{b}{a}$.
The axis of symmetry will be at the vertex ....where x = -3 this is also = -b/2a
-b/2a = -3 multiply both sides by -2
b/a = 6