Can u guys help me PLZ

I assume this is meant to be x = 1/(3x) + 5

 

If so, multiply all terms by 3x, to get. 3x² = 1 + 15x

 

Subtract 1 + 15x from both sides:  3x² - 15x - 1 = 0

 

This is a quadratic equation so the two solutions are given by:

 

x₁ = (15 + sqrt(15² - 4*3*(-1)))/(2*3) → (15 + sqrt(237))/6

 

x₂ = (15 - sqrt(152 - 4*3*(-1)))/(2*3) → (15 - sqrt(237))/6

 

If the original equation is meant to be x = 1/(3x + 5) then multiply through by 3x + 5 to get

3x² + 5x = 1.  Subtract 1 from both sides: 

 

3x² + 5x -1 = 0

 

The solutions are:

 

x₁ = (-5 + sqrt(25 + 12))/6 → (-5 + sqrt(37))/6

 

x₂ = (-5 sqrt(37))/6