Three red and two blue balls are placed in a hat. A ball is chosen at random and not replaced. A second ball is chosen at random. What is the probability that both balls chosen will be red
+36916 First one red there are 5 balls three red so 3/5 chance
now there are 4 balls left two are red 2/4 chance of red
3/5 * 2/4 = 6/20 = 3/10
