Can you help me please???
For what kind of integers numbers of "a", both solutions of the equation: x^2 + ax + 6= 0, are integers numbers ?
with solutions I refer the two numbers that make the equation = 0
and I think it has to do with Vieta's formulas.
+33616 What two integers multiplied together make 6.
A. 1 and 6
B. -1 and -6
C. 2 and 3
D. -2 and -3
The sum of these must equal a, so:
A. a = 7 x2 + 7x + 6 → (x + 1)(x + 6) =0 solutions are x = -1 and x = -6
B. a = -7 x2 - 7x + 6 → (x - 1)(x - 6) =0 solutions are x = 1 and x = 6
C. a = 5 x2 + 5x + 6 → (x + 2)(x + 3) =0 solutions are x = -2 and x = -3
D. a = -5 x2 - 5x + 6 → (x - 2)(x - 3) =0 solutions are x = 2 and x = 3
.
+33616 What two integers multiplied together make 6.
A. 1 and 6
B. -1 and -6
C. 2 and 3
D. -2 and -3
The sum of these must equal a, so:
A. a = 7 x2 + 7x + 6 → (x + 1)(x + 6) =0 solutions are x = -1 and x = -6
B. a = -7 x2 - 7x + 6 → (x - 1)(x - 6) =0 solutions are x = 1 and x = 6
C. a = 5 x2 + 5x + 6 → (x + 2)(x + 3) =0 solutions are x = -2 and x = -3
D. a = -5 x2 - 5x + 6 → (x - 2)(x - 3) =0 solutions are x = 2 and x = 3
.
