$$log \frac{3}{x}+log x^{2}+ 3 log (3x)$$
So we have, using a property of logs.....
log(3/x) + log(x^2) + log(3x)^3 =
log(3/x) + log(x^2) + log (27x^3) .....and by another property pf logs, we have
log((3/x)*(x^2)*(27x^3)) =
log (81x^4)
We could also write this as log(3x)^4 = 4 log(3x)
