Simplify the following:
(8 y-10 z)/2-(3 y+z)
Put each term in (8 y-10 z)/2-(3 y+z) over the common denominator 2: (8 y-10 z)/2-(3 y+z) = (8 y-10 z)/2+(2 (-3 y-z))/2:
(8 y-10 z)/2+(2 (-3 y-z))/2
(8 y-10 z)/2+(2 (-3 y-z))/2=((8 y-10 z)+2 (-3 y-z))/2:
(8 y-10 z+2 (-3 y-z))/2
2 (-3 y-z)=-6 y-2 z:
(8 y-10 z+-6 y-2 z)/2
Grouping like terms, 8 y-10 z-6 y-2 z=(8 y-6 y)+(-10 z-2 z):
((8 y-6 y)+(-10 z-2 z))/2
-10 z-2 z=-12 z:
(-12 z+(8 y-6 y))/2
8 y-6 y=2 y:
(2 y-12 z)/2
Factor 2 out of 2 y-12 z:
2 (y-6 z)/2
(2 (y-6 z))/2=2/2×(y-6 z)=y-6 z:
Answer: | y - 6z
