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Three consecutive even integers such that the sum of twice the smallest, one less than the middle, and four more than the largest is -15

 Oct 1, 2018
edited by Guest  Oct 1, 2018
 #1
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Let the integers be:

n,  n + 2,  n  + 4

 

2n + (n + 2) - 1 + (n + 4) + 4 = -15

4n - 1 + 10 = -15

4n + 9 = -15

4n = -15 - 9

4n = - 24

n = - 6 - the smallest number

-6 + 2 = - 4 - the middle number.

-6 + 4 = - 2 - the largest number.

 Oct 2, 2018

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