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Let f(x) = 3(x - 6)^2 + 1. What is the range of f?

 Mar 2, 2019
 #1
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We have a    parabola that opens upward......the vertex is (6, 1)

 

The y value of 1 is the minimum value on the graph......so....the range is   [ 1, infinity )

 

 

 

cool cool cool

 Mar 3, 2019

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