cant figure this out

    \(1\frac25-\frac48\)

                                  \(\frac48\)  is the same as  \(\frac12\)

=  \(1\frac25-\frac12\)

                                  \(1\frac25\)  is the same as   \(1+\frac25\)

=  \(1+\frac25-\frac12\)

                                  Now we need a common denominator. Multiply and divide  1  by  10 .

=  \(\frac{10}{10}+\frac25-\frac12\)

                                  Multiply and divide  \(\frac25\)  by  2 .

=  \(\frac{10}{10}+\frac{2*2}{5*2}-\frac12\)

 

=  \(\frac{10}{10}+\frac{4}{10}-\frac12\)

                                  Multiply and divide  \(\frac12\)  by  5 .

=  \(\frac{10}{10}+\frac{4}{10}-\frac{1*5}{2*5}\)

 

=  \(\frac{10}{10}+\frac{4}{10}-\frac{5}{10}\)

 

10 apples + 4 apples - 5 apples  =  9 apples   So

10 tenths + 4 tenths - 5 tenths  =  9 tenths

 

= \(\frac9{10}\)