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carol is in the skydeck of the sears tower ovelooking lake michian. she sights two sailboats going due east from the tower . the angles of depression to the two boats are 42 degrees and 29 degress. if the skydeck is 1335 feet high, how far apart are the boats?

 Nov 21, 2014

Best Answer 

 #1
avatar+118723 
+10

Draw a picture first.

Let the distance of the furthest boat be F  and the dist of  the closer one be C

You want F - C

--------

tan 42 = 1335/C

solve this for C

tan 29=1335 / F

Solve for F

do the subtraction.

----------------

Try to work it out from what I have written but you are welcome to ask for more help if you need it :)

 Nov 21, 2014
 #1
avatar+118723 
+10
Best Answer

Draw a picture first.

Let the distance of the furthest boat be F  and the dist of  the closer one be C

You want F - C

--------

tan 42 = 1335/C

solve this for C

tan 29=1335 / F

Solve for F

do the subtraction.

----------------

Try to work it out from what I have written but you are welcome to ask for more help if you need it :)

Melody Nov 21, 2014
 #2
avatar+130511 
+5

We can figure this, thusly

d = 1335 [ tan61 - tan48] = about 925.74 ft

 

 Nov 21, 2014

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