+16 Question:
Find the equation whose graph is shown below. Write your answer in standard form.
(Standard form is A (x) + B (y) =C, where A is positive, and A, B, and C are integers with the greatest common divisor 1.)
It seems I can't put any images or links, so I'll just list out some of the plots on this line:
(-5, -2), ( -1, -1), ( 3, 0).
+394 Pick any two points, I chose (3, 0) and (-1, -1).
Calculate slope:
\(\frac{-1 - 0}{-1 - 3}=\frac{1}{4}\)
From slope-intercept form, you know the equation is
y = (1/4)x + b
Plug in any point to find b. I chose (3, 0)
0 = (1/4)*3 + b
b = -(3/4)
Therefore the equation is
y = (1/4)x - (3/4)
To get into the desired form, subtract (1/4)x from both sides then multiply by lcm
-(1/4)x + y = -(3/4)
x - 4y = 3, is the equation in standard form.
+394 Pick any two points, I chose (3, 0) and (-1, -1).
Calculate slope:
\(\frac{-1 - 0}{-1 - 3}=\frac{1}{4}\)
From slope-intercept form, you know the equation is
y = (1/4)x + b
Plug in any point to find b. I chose (3, 0)
0 = (1/4)*3 + b
b = -(3/4)
Therefore the equation is
y = (1/4)x - (3/4)
To get into the desired form, subtract (1/4)x from both sides then multiply by lcm
-(1/4)x + y = -(3/4)
x - 4y = 3, is the equation in standard form.
