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Let \(a,b,c\)   be positive real numbers such that \(a + b + c = 1\). Find the minimum value of

\(\frac{1}{a + 2b} + \frac{1}{b + 2c} + \frac{1}{c + 2a}.\)

 Jan 7, 2022
 #1
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The minimum value is 3/4.

 Jan 7, 2022
 #2
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I believe it is 3....

because 1/3/4 is equal to 4/3, which is greater than one....

I'm pretty shure I am wrong so @guest can you give an explanation?

 Jan 7, 2022

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