Let \(a,b,c\) be positive real numbers such that \(a + b + c = 1\). Find the minimum value of

\(\frac{1}{a + 2b} + \frac{1}{b + 2c} + \frac{1}{c + 2a}.\)

Guest Jan 7, 2022

#2**+1 **

I believe it is 3....

because 1/3/4 is equal to 4/3, which is greater than one....

I'm pretty shure I am wrong so @guest can you give an explanation?

XxmathguyxX Jan 7, 2022