Let \(a,b,c\) be positive real numbers such that \(a + b + c = 1\). Find the minimum value of
\(\frac{1}{a + 2b} + \frac{1}{b + 2c} + \frac{1}{c + 2a}.\)
I believe it is 3....
because 1/3/4 is equal to 4/3, which is greater than one....
I'm pretty shure I am wrong so @guest can you give an explanation?