Ch.2

The first aircraft has 5959 more seats than the second aircraft. The third aircraft has 4747 fewer seats than the second aircraft. If their total number of seats is 402402​, find the number of seats for each aircraft

 

Let the number of seats of the 2nd aircraft=S

The number of seats of the 1st aircraft =S + 5959

The number of seats of the 3rd aircraft =S - 4747

 

S + (S+5959)+(S-4747) =402402, solve for S

S = 133,730 number of seats of 2nd aircraft

133,730 + 5959 =139,689 number of seats of the 1st aircraft.

133,730 -4747 =128,983 number of seats of the 3rd aircraft

So that: 133,730 + 139,689 + 128,983 =402,402 total number of seats.

P.S. Did you dream this one up??!!.

59, 47 and 402 makes more sense to me

 

S + (S + 59) + (S - 47) = 402

3S = 390

S = 130

 

1st plane has 189 seats

2nd plane has 130 seats

3rd plane has 83 seats