+201 1. Imelda, Susan, and Clara are driving go-carts around a track. Imelda takes 14 minutes, Susan takes 9 minutes, adn Clara takes 10 minutes to drive one lap. Suppose all three of them start together at a point and drive at their same speeds. After how many minutes will all three meet again?
2. How many squares with sides that are 6 inchess long are needed to cover a square with a side length of 30 inches without overlapping?
+129849 For the first one, we just need to find the least common multiple for 9, 10 and 14,,,,so we have
9 = 32
10 = 2 * 5
14 = 2 * 7
So the least common multilple is 32 * 2 * 5 * 7 = 630. And they will meet agiain in 630 minutes = 10.5 hrs.!!! (Hope they don't run out of gas!!)
For the second one....there will 5 rows of 5 squares each = 25 squares. To see this, note that the area of the big square = 900sq in. And the area of each little square = 36sq in So, 900/36 = 25 !!
+23252 1) To find when 14, 9, and 10 all meet, find the lowest common multiple:
14 = 2 x 7
9 = 3 x 3
10 = 5 x 2
Lowest common multiple = 2 x 7 x 3 x 3 x 5 = 630 minutes
2) It takes 5 squares of 6" each to reach 30"
Since there will 5 squares in both directions, it will take 25 squares.
Another way to solve the problem: 30" x 30" square is a total of 900 sq inches
Each square is 6" x 6" = 36 square inches.
Divide 900 sq in by 36 sq in to get 25 squares
+129849 For the first one, we just need to find the least common multiple for 9, 10 and 14,,,,so we have
9 = 32
10 = 2 * 5
14 = 2 * 7
So the least common multilple is 32 * 2 * 5 * 7 = 630. And they will meet agiain in 630 minutes = 10.5 hrs.!!! (Hope they don't run out of gas!!)
For the second one....there will 5 rows of 5 squares each = 25 squares. To see this, note that the area of the big square = 900sq in. And the area of each little square = 36sq in So, 900/36 = 25 !!
