What is the equation of the line in standard form?
The points are (-3,2)(2,-1)
I got
3𝑥+−5𝑦=1
Maybe another slight sign error.....???
Slope
[ -1 - 2 ] / [ 2 - - 3 ] = -3/ 5
Using (2, -1) we have
y = (-3/5) ( x - 2) - 1 multiply through by the denominator of the fraction ⇒ 5
5y = -3(x - 2) - 5 implify
5y = -3x + 6 - 5
5y = -3x + 1 add 3x to both sides
3x + 5y = 1
Note that we can check to see if this is true...plugging in the original points should both make sense
3(2) + 5(-1) = 1
6 - 5 = 1 is true and
3(-3) + 5(2) = 1
-9 + 10 = 1 is also true