We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
154
1
avatar+701 

What is the equation of the line in standard form?

The points are (-3,2)(2,-1)

 

I got 

3𝑥+−5𝑦=1

 Oct 23, 2018
 #1
avatar+100571 
+2

Maybe another slight sign error.....???

 

Slope

 

[ -1 - 2 ]  / [ 2 - - 3 ]  =  -3/ 5

 

Using  (2, -1)  we have

 

y  = (-3/5) ( x - 2)  - 1        multiply through by the denominator of the fraction ⇒  5

 

5y = -3(x - 2) - 5     implify

 

5y  = -3x + 6 - 5

 

5y  =   -3x + 1     add 3x to  both sides

 

3x + 5y   =  1

 

Note that we can check to see if this is true...plugging in the original points should both make sense

 

3(2) + 5(-1)  =  1 

6  - 5  = 1         is true     and

 

3(-3) + 5(2)  =  1   

-9 + 10  =  1         is also true

 

 

cool cool cool

 Oct 23, 2018

7 Online Users