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What is the equation of the line in standard form?

The points are (-3,2)(2,-1)

 

I got 

3𝑥+−5𝑦=1

hoiuu  Oct 23, 2018
 #1
avatar+90969 
+2

Maybe another slight sign error.....???

 

Slope

 

[ -1 - 2 ]  / [ 2 - - 3 ]  =  -3/ 5

 

Using  (2, -1)  we have

 

y  = (-3/5) ( x - 2)  - 1        multiply through by the denominator of the fraction ⇒  5

 

5y = -3(x - 2) - 5     implify

 

5y  = -3x + 6 - 5

 

5y  =   -3x + 1     add 3x to  both sides

 

3x + 5y   =  1

 

Note that we can check to see if this is true...plugging in the original points should both make sense

 

3(2) + 5(-1)  =  1 

6  - 5  = 1         is true     and

 

3(-3) + 5(2)  =  1   

-9 + 10  =  1         is also true

 

 

cool cool cool

CPhill  Oct 23, 2018

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