I filled in the answers but just need to know if I am right.
Right △EFG has its right angle at F, EG=8, and FG=6.
What is the value of the trigonometric ratio of an angle of the triangle?
The hypotenuse is EG = 8
FG = 6
So.... EF = sqrt (8^2 - 6^2) = sqrt (64 - 36) = sqrt ( 28) = 2sqrt (7)
sin E = FG / EG = 6/8 = 3/4
cot G = FG / EF = 6/ (2sqrt (7) = 3sqrt (7) / 7
sec G = EG / FG = 8 / 6 = 4/3
E
2sqrt (7) 8
F 6 G
GOOD JOB, Spring !!!!
Thank you so much for all your help CPhill!
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