+0  
 
0
75
2
avatar+133 

I filled in the answers but just need to know if I am right.

 

Right △EFG has its right angle at F, EG=8, and FG=6.

What is the value of the trigonometric ratio of an angle of the triangle?

 

 Nov 30, 2020
 #1
avatar+116126 
+1

The hypotenuse  is  EG  =   8

FG  = 6

So....  EF      =    sqrt  (8^2 - 6^2)  = sqrt  (64  - 36) =  sqrt  ( 28)  =  2sqrt (7)

 

 

sin E  =   FG / EG =   6/8   =  3/4

 

cot G  =   FG / EF  =    6/ (2sqrt (7)  =   3sqrt (7)  / 7

 

sec G =   EG / FG  =  8 / 6  =  4/3

 

 

E

 

2sqrt (7)           8

 

F             6                         G

 

GOOD JOB, Spring   !!!!

 

 

cool cool cool

 Nov 30, 2020
 #2
avatar+133 
+1

Thank you so much for all your help CPhill! smiley

Spring  Nov 30, 2020

26 Online Users

avatar
avatar