Find the mass of oxygen contained in 860.0 grams of magnesium nitrate ( Mg(NO3)2 )
+37084 You'll need to look at a periodic table to get all of the molecular weights
Mg=24.305 =24.305
N =14.007 x 2 =28.014 (there are TWO N's in each molecule)
O=15.999 x 6 = 95.994 (there are SIX O's in each molecule)
Total = =148.313
The FRACTION of this total that is Oxygen is 95.994/148.313 of the total
99.994/148.313 x 860 = 556.63 grams of oxygen
+37084 Messed up on the last calculation....numerator should be 95.994
95.994/148.313 x 860 = 556.63 gm <---------I had the correct answer but did not enter the numbers correctly
