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A gas at 155 kPa and 25°C has an initial volume of 1.00 L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume? I am getting an answer smaller than the original volume, does that make sense?

 Apr 17, 2016
 #1
avatar+130511 
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Using

 

P1 V1       =     P2 V2

  T1                   T2

 

We have

 

155 * 1     =   605 * V2

  25                  125

 

Solving for V2, we have

 

(155 * 125)     =   V2    =  about 1.281 L

 (25 * 605) 

 

 

 

cool cool cool

 Apr 17, 2016
 #2
avatar+33661 
+5

Not quite Chris!  The temperatures must be absolute;  T1 = 273+25 and T2 = 273+125,  so the final volume will be smaller than the initial volume because the pressure increses far more than tha temperature.

 Apr 17, 2016

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