+0  
 
0
215
1
avatar

how many Fe atoms are contained in 787 g of Fe

Guest Sep 11, 2017
 #1
avatar
0

Since the molar mass of Fe = 55.845 g/mol = 6.022 x 10^23 atoms. It, therefore, follows that:

787g contain = (787 / 55.845) x (6.022 x 10^23) = 8.487  x  10^24 atoms.

Guest Sep 11, 2017

26 Online Users

avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.