+0  
 
0
28
1
avatar

how many Fe atoms are contained in 787 g of Fe

Guest Sep 11, 2017
Sort: 

1+0 Answers

 #1
avatar
0

Since the molar mass of Fe = 55.845 g/mol = 6.022 x 10^23 atoms. It, therefore, follows that:

787g contain = (787 / 55.845) x (6.022 x 10^23) = 8.487  x  10^24 atoms.

Guest Sep 11, 2017

5 Online Users

avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details