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how many Fe atoms are contained in 787 g of Fe

Guest Sep 11, 2017
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Since the molar mass of Fe = 55.845 g/mol = 6.022 x 10^23 atoms. It, therefore, follows that:

787g contain = (787 / 55.845) x (6.022 x 10^23) = 8.487  x  10^24 atoms.

Guest Sep 11, 2017

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