1. If I have 672 grams of oxygen (O2) gas at 78 atm and 900K, what is the volume of the gas?

A) 15.0 L

B) 19.9 L

C) No change

2. What is the temperature of 4 moles of gas at a pressure of 5.6 atm and 12 L? Expressed in Kelvin.

NOTE: I know this should be off-topic but it won't work for me. Sorry!

Guest Nov 27, 2018

edited by
Guest
Nov 27, 2018

#1**+1 **

PV=nRT n = number of moles of O2 Molar weight of O2 = 32 gm 672/32= 21 moles

78 (V) = (21)(.08206)(900) Solve for V= 19.88 Liters

2. PV = nRT

n = 4 P = 5.6 V = 12 R = .08206 Plug in and solve for T (which will be in K degrees)

ElectricPavlov Nov 27, 2018