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1. If I have 672 grams of oxygen (O2) gas at 78 atm and 900K, what is the volume of the gas?

A) 15.0 L

B) 19.9 L

C) No change

 

2. What is the temperature of 4 moles of gas at a pressure of 5.6 atm and 12 L? Expressed in Kelvin.

 

 

NOTE: I know this should be off-topic but it won't work for me. Sorry!

Guest Nov 27, 2018
edited by Guest  Nov 27, 2018
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PV=nRT       n = number of moles of O2     Molar weight of O2 = 32 gm   672/32= 21 moles

 

78 (V) =  (21)(.08206)(900)      Solve for V= 19.88 Liters

 

 

 

2.    PV = nRT  

       n = 4    P = 5.6   V = 12   R = .08206      Plug in and solve for T (which will be in K degrees)

ElectricPavlov  Nov 27, 2018

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