1. If I have 672 grams of oxygen (O2) gas at 78 atm and 900K, what is the volume of the gas?
A) 15.0 L
B) 19.9 L
C) No change
2. What is the temperature of 4 moles of gas at a pressure of 5.6 atm and 12 L? Expressed in Kelvin.
NOTE: I know this should be off-topic but it won't work for me. Sorry!
+36916 PV=nRT n = number of moles of O2 Molar weight of O2 = 32 gm 672/32= 21 moles
78 (V) = (21)(.08206)(900) Solve for V= 19.88 Liters
2. PV = nRT
n = 4 P = 5.6 V = 12 R = .08206 Plug in and solve for T (which will be in K degrees)
