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An electron traveling at 2.2×105m/s has an uncertainty in its velocity of 5.06×104m/s . What is the uncertainty in its position?
 Oct 15, 2013
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Uncertainty principle says that delta(x)*delta(p) >= h/(4*Pi)
p=gamma * m * v = 1/(Sqrt(1- v^2/c^2)) * m * v

where delta(x) and delta(p) are the unsertainys of position and momentum respectively, h is the planc's constant, v is the measured speed of the electron, m is the rest mass of an electron.

From there we can solve that:

delta(x) >= (h*Sqrt(1-v^2/c^2)/(4* Pi*m*delta(v)

just pit in the values and you get that delta(x) >= 1.1nm
 Oct 15, 2013

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