How many grams would be in 2.3 times 10 to the power of 24 atoms of silver?
It would be the mass of 2.3 × 10²⁴ Ag atoms is about 410 g. I'm not the brightest at chemistry and I don't think this website is for chemistry but I recall some of this stuff.
Convert from atoms to grams:
2.3×10^24 atoms silver (Ag)
Determine the number of atoms, N_atoms:
N_atoms = 2.3×10^24 atoms
Look up Avogadro's constant, N_A, to find the number of atoms in a mole:
N_A = 6.022×10^23 atoms/mol
Divide N_atoms by N_A to convert to the amount of substance, n:
n = N_atoms/N_A = N_atoms/1×1/N_A = (2.3×10^24 atoms)/1×(1 mol)/(6.022×10^23 atoms) = 3.819 mol
Determine the molar mass, M, of Ag:
M = 107.8682 g/mol
Multiply n by M to convert to the mass, m:
m = n×M = (3.819 mol)/1×(107.8682 g)/(1 mol) = 411.9745 g