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The famous German composer, Johann Sebastian Bach, had 20 children from 2 wives. Unfortunately most of them died in their childhood. The question is this:

1- What is the probability that 12 were girls and 8 boys.

2- What is the probability that 6 were boys and 14 girls.

Thank you for help.

 Feb 9, 2018
 #1
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1.  12 girls - 8 boys  =

 

We can choose   any 12 of the 20  to be girls  ....so we have ...

 

C(20, 12) * .5^20   ≈ .12   ≈  12%

 

2.  6 boys - 14 girls

 

We can choose  any 14 of the 20 to be girls...so we have

 

C(20, 14) * .5^20  ≈  .0369  ≈   3.7%

 

 

cool cool cool

 Feb 9, 2018

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