chocolate coin problem

if i have 1 chocolate coin that measures from one side of the coin to the other 4 cm and i also have two chocolate coins that measure 3 cm from one side to another tell me witch is bigger the one chocolate coin or the two smaller ones

A1 = (4² * π / 4) = 16 * π / 4

A2 = 2 * (3² * π / 4) = 2 * 9 * π / 4 = 18 * π / 4

A2 > A1

The two chocolate coins are together more than the larger chocolate coin.

!

Assuming your chocolate coin are circular, then we have:

Area =r^.Pi

A = (4/2)^2 . Pi=4 x 3.141592 =12.57 cm^2

A = (3/2)^2 . Pi=2.25 x 3.141592 =7.07 cm^2

7.07 x 2 =14.14 cm^2

So, the two 3-cm diameter are larger than the single 4-cm diameter by:

14.14 - 12.57 =1.57 cm^2