+73 7x^2 + nx - 11
Note that we have
(7x - 11) (x + 1) = 7x^2 - 11x + 7x - 11 = 7x^2 - 4x - 11
(7x - 1) (x + 11) = 7x^2 -1x + 77x - 11 = 7x^2 + 76x - 11
(7x + 11) (x - 1) = 7x^2 + 11x - 7x - 11 = 7x^2 + 4x -11
(7x + 1) (x - 11) = 7x^2 - 77x +1x - 11 = 7x^2 - 76x - 11
So what are the actual possible values of $n$?
Also, another question that is apparently identicle to this you answered with :
7x^2 + nx - 11
7 and 11 are prime....so the possible factorizations are
(7x + 11) ( x + 1) ⇒ n = 18
(7x + 1) (x + 11) ⇒ n = 78
(-7x + 1)(-x + 11) ⇒ n = -78
(7x - 11) ( x - 1) ⇒ n = -18
Big Confused,
MS
