What is the result of the following expression?:
[1 + 9^-4^(6*7)]^3^2^85=? No cheating! You may use any calculator except Wolfram/Alpha!!!
The result is accurate to 18 trillion trillion digits!!!.
A few pointers:
1) Find the result inside the square brackets [ ].
2) Raise that result to the power 3^2^85, beginning from the right (2^85) raised to the power 3.
3) Raise the obtained result in 1 to the result obtained in 2 above.
4) This is what is called a "pan-digital formula", in the sense that it uses all numbers from 1 to 9.
5) Good luck to all and Merry Chrismas.
Melody: I thought I should keep everybody entertained over the Christmas holidays!!.
OK folks. I figured it out and the result is: Euler's constant "e". But, I was only able to get 160 accurate digits!.Let us see if anybody can improve on that!.
+36923 Just a FYI:
Before we go too far down this thread, a little clarification.....this is generally referrd to as Euler's NUMBER ..... Euler's CONSTANT is something else.
Happy Hanukkah ! .... or Merry Christmas Eve..... Or Kwanzaa (26th)....
.....or just "Have a nice day"
I was able to get: 16,034 accurate digits!!. That is the end of my attempts! My large-number calculator simply stalls on number greater than that.
+36923 Holy Cow!!!! That is incredible....don't know what you are going to DO with it, but it is pretty cool.
This isn't mental gymnastics -- the computer is doing all the work.
It is like mental msturbation, though!
EP: Sorry, but you are "dead wrong!!". You try and get just a few hundred accurate digits, using the expression as it is written down, and you will have tough time doing it. You have to come up with some tricks and some clever shortcuts to be able to do what I did, because the "exponent" is such a huge number that most arbitrary precision calculators cannot handle it.
+36923 That wasn't my comment...it was a comment FROM someone TO me..... I thought it was cool!
