+23 A certain circle can be represented by the following equation.
x^2+y^2+6x+2y-6=0
What is the center of this circle ?
What is the radius of this circle ?
+23 Ok, finally figured it out-
so we have x^2+y^2+2y+6x-6=0
then we put the x wuith the x and the y with the ys.
x^2+6x+y^2+2y=6
then we complete the square for both x and y
x^2+6x+9+y^2+2y+1=6+9+1
simplify
(x+3)^2+(y+1)^2=16
x=-3
y=-1
radius=4
