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A certain circle can be represented by the following equation.

x^2+y^2+6x+2y-6=0

What is the center of this circle ?

 

What is the radius of this circle ?

 Jun 13, 2019
edited by ProffesorNobody  Jun 13, 2019
 #1
avatar+25 
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Ok, finally figured it out-

so we have x^2+y^2+2y+6x-6=0

then we put the x wuith the x and the y with the ys. 

x^2+6x+y^2+2y=6

then we complete the square for both x and y

x^2+6x+9+y^2+2y+1=6+9+1

simplify

(x+3)^2+(y+1)^2=16

x=-3

y=-1

radius=4

 Jun 13, 2019

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