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Find the equation of the circle centered at (2,2) and passing through (4,5).

 Feb 20, 2021
 #1
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Actually, all we  need to do here is to find the  radius ^2.....this is  

 

  [  (4 - 2)^2  +  ( 5  -2)^2  ]  =     [ 2^2  + 3^2 ]  =    13

 

So.......the equation is

 

( x  - 2)^2  +  (y  - 2)^2     = 13

 

 

cool cool cool

 Feb 20, 2021

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