Anyone can help me out with this? Kinda stuff with it working out the angles
+130118 (a) connect AB
minor arc BA = 2*angle ACB = 2 * 37 = 74°
Since TA is a tangent, then angle TAB = 1/2 minor arc BA = (1/2) (74) = 37
So, in triangle ABT, angle ABT = 180 - 42 - 37 = 101°
(b) Since CA is a transversal cutting parallel lines....then angles ACB and CAD are equal
And minor arcs BA and CD are equal since they are subtended by equal angles....and their measures = 2 * 37 = 74°
And by the intersecting chord theorem angle AEB =(1/2) (minor arc BA + minor arc CD) = (1/2) (74 + 74) = 74°
(c) angle EAD = angle CAD = 37°
