Let R be the circle centered at (0,0) with radius 10. The lines x=6 and y=5 divide R into four regions R1,R2,R3, and R4. Let [Ri] denote the area of region Ri. If [R1]>[R2]>[R3]>[R4],then find [R1]−[R2]−[R3]+[R4].
By calculus,
[R1]=30+14⋅π⋅102+∫50√100−x2 dx+∫60√100−x2 dx.
We can write out the areas similarly, to get [R_1] - [R_2] - [R_3] + [R_4] = 80.
Just a picture for those who want to see:
i solved it already, but thanks for trying to help! the answer was 120.