Circle Question

First find the area of the SECTOR of the circle.....

  Then SUBTRACT the area of the TRIANGLE....

 

r= 11km     Area of CIRCLE = pi x r^2 = 3.14 x 11^2 = 380.132 sq km

Area of SECTOR =   60/360  x  380.132 = 63.355 sq km

Area of triangle = (equalateral triangle) = A = (sqrt3)/4  x 11^2 = 52.395 sq km

 

Area Sector - Area Triangle = area segemnt =      63.355 - 52.395 = 10.96 sq km