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Can someone please help me with this question? It would mean a lot to me!

 

A circle passes through the points (-2,0), (2,0), and (3,2). Find the center of the circle. Enter your answer as an ordered pair.

 

Thank you so much!

 Jul 26, 2020
 #1
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If (x,y) is the center of the circle and r is the radius, then
 

(x + 2)^2 + y^2 = r^2

(x - 2)^2 + y^2 = r^2

(x - 3)^2 + (y - 2)^2 = r^2

 

Subract equations:

 

8x + 2y - 9 = 0

x + 6y -  9 = 0

 

Solve: (x,y) = (18/23, 63/46)

 Jul 27, 2020
 #2
avatar+12484 
+2

A circle passes through the points (-2,0), (2,0), and (3,2). Find the center of the circle. Enter your answer as an ordered pair.

 

laugh

 Jul 27, 2020
 #3
avatar+213 
0

Thank you so much! Your explanation really helped!

Caffeine  Jul 27, 2020

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