Can someone please help me with this question? It would mean a lot to me!
A circle passes through the points (-2,0), (2,0), and (3,2). Find the center of the circle. Enter your answer as an ordered pair.
Thank you so much!
If (x,y) is the center of the circle and r is the radius, then
(x + 2)^2 + y^2 = r^2
(x - 2)^2 + y^2 = r^2
(x - 3)^2 + (y - 2)^2 = r^2
Subract equations:
8x + 2y - 9 = 0
x + 6y - 9 = 0
Solve: (x,y) = (18/23, 63/46)
Thank you so much! Your explanation really helped!
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