By how much should you reduce the radius of a circle with circumference of 48pi cm in order to reduce its area by 47 pi?
Area of the circle before reduction
pi d = circumference pi d = 48 pi so d = 48 and radius = 24
pi r^2 = pi 24^2 = 576 pi
reducit it by 47 pi = 529 pi
now find reduced radius pi r^2 = 529 pi
r^2 = 529 r = 23
Origianl radius was 24 reduce it by ONE to get to new radius of 23