+0  
 
0
796
1
avatar

The circumference of the circle C subscript 1 is 9 cm and the circumference of C subscript is 2 pi cm. what is the value of the ratio of the areas of C subscript 1 to C subscript 2

 May 11, 2016
 #1
avatar+37170 
0

c1   pi x d = 9     so d= 9/pi   radius = 9/(2pi)     Area = pi r^2   pi (9/(2pi))^2 =  pi (81/(4pi^2) =81/(4pi)

 

c2                            d=2pi/pi =2   radius =1     Area = pi r^2   = pi

 

ratio area c1/c2 =     81/(4pi)  /  pi =   81 / (4pi^2)

 

 

 

Are you sure the first circle c1 circumference was not 9pi ??   If it was, the ratio works out to 20.25     (the same as 9^2 / 2^2)

 May 11, 2016
edited by ElectricPavlov  May 11, 2016
edited by ElectricPavlov  May 11, 2016
edited by ElectricPavlov  May 11, 2016

1 Online Users