Let A, B, and C be points on a circle of radius 18. If angle ACB = 170 degrees, what is the circumference of the minor arc {AB}? Express your answer in terms of pi.
+421 Inscribed arc = 1/2 * arc measure
170 * 2 = 340
340/360 = 34/36 = 17/18 of the whole circle --> 18^2 * 17/18 * pi = 17*18 = 306 pi
+1641 170º * 2 = 340º This is a major arc.
Minor arc is 360º - 340º = 20º
Minor arc {AB} = (36pi/360)*20 = 2pi
btw, major arc = 34pi
+421 Oops... sorry, I meant to say that the minor arc must have 360-340 =20 degrees of measure, so it is 1/18 * 2 * 18 * pi = 2pi
Somehow I found the wrong area using the diameter ^^
