The center of the circle with equation x^2+y^2=4x-12y-39 is the point (h,k). What is h+k?
The center of the circle with equation x^2+y^2=4x-12y-39 is the point (h,k). What is h+k?
x^2+y^2=4x-12y-39
rearrange (x2 – 4x + ) + (y2 + 12y + ) = –39
complete the squares
add same amount both sides (x2 – 4x + 4) + (y2 + 12y + 36) = –39 + 4 + 36
(x – 2)2 + (y + 6)2 = 1
h = 2 k = – 6
h + k = (+2) + (–6) = – 4
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