The equation of a circle is given as 2x^2 + 2y^2 + 4x + 12y + 6 = 0. What are the center, C, and the radius, r of the circle?
2x^2 + 2y^2 + 4x + 12y + 6 = 0 Divide by 2
x^2 + 2x + y^2 + 6y = -6 'Complete the square' for x and y
(x+1)2 + (y+3)2 = -6 + 2 + 9 = 5 5 is radius2 radius = sqrt 5
center is (-1,-3)