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The equation of a circle is given as 2x^2 + 2y^2 + 4x + 12y + 6 = 0.  What are the center, C, and the radius, r of the circle?

 Feb 17, 2021
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2x^2 + 2y^2 + 4x + 12y + 6 = 0     Divide by 2

x^2 + 2x       + y^2 + 6y    = -6        'Complete the square' for x and y

(x+1)2           + (y+3)2       = -6 + 2 + 9  = 5              5 is radius2      radius = sqrt 5

                          center is (-1,-3)

 Feb 17, 2021

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