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circle A has its center at A(3,2) and line CB is tangent to circle A at B(6,4). Find the slope of line CB.

ZinniaHeliantheae  May 18, 2017
 #1
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Since CB is tangent to the circle at B, it  will have a negative reciprocal slope to radius AB

 

Slope AB  =   [ 4 -2] / [ 6 - 3 ] =    2/3

 

So.....the slope of BC  =    -3/2

 

 

 

cool cool cool

CPhill  May 18, 2017

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