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Points $L$ and $M$ lie on a circle $\omega_1$ centered at $O$.  The circle $\omega_2$ passing through points $O,$ $L,$ and $M$ is drawn.  If the measure of arc $LM$ in circle $\omega_1$ is $90^\circ,$ and the radius of $\omega_1$ is 1, then find the area of triangle $LOM$.

 

 Mar 21, 2024
 #1
avatar+128794 
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Area  = (1/2) (1^2) sin 90°  =  1/2

 

cool cool cool

 Mar 21, 2024

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