With the hyperbolic equation 4x2 - y2 + 8x - 4y - 4 = 0, are the asymptotes y = (+,-) (4x + 4) - 2
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4x^2 - y^2 + 8x - 4y - 4 = 0
Complete the square on x and y
4[x^2 + 2x + 1] - [y^2 + 4y + 4] = 4 + 4 - 4 factor and simplify
4 ( x + 1)^2 - ( y + 2)^2 = 4 divide through by 4
(x + 1)^2 - (y + 2)^2 / 4 = 1 and we can put this in standard form as
(x + 1)^2 - (y + 2)^2 = 1
1 4
The equation of the asymptotes is given by :
y = ± (b/a)(x - h) + k and b = 2, a = 1, h = -1 and k = -2 so we have
y = ± (2/1) (x - -1) + (- 2) which simplifies to
y = ± 2(x + 1) - 2
So the two two equations of the asymptotes further simplify to :
y = 2x and y = -2x - 4
Here's the graph, Shades : https://www.desmos.com/calculator/hguyqxzlql