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avatar+956 

I found the derivative of the function: y' = \( 3 \sqrt{x} \over 2x \)-1 

Then I plugged in 4, and I got -1/4. Is that correct?

 Feb 21, 2018
 #1
avatar+99586 
+3

y  = 3(x)^(1/2) - x

 

y'  =  (3/2)x^(-1/2)  - 1

 

So..... the slope  at  x  =  4  =   (3/2) (4)^(-1/2)  - 1   =  (3/2) / √4  - 1  =  (3/4) - 1  =  -1/4

 

Correct  !!!

 

 

cool cool cool

 Feb 21, 2018
 #2
avatar+4095 
+4

Beautiful explanation, CPhill! I like it! 

tertre  Feb 21, 2018
 #3
avatar+99586 
+3

Thanks, tertre   !!!

 

 

cool cool cool

CPhill  Feb 21, 2018
 #4
avatar+956 
+1

CPhill always got the best explanation! 

 

Just wanted to thank you for all your help. :) 

 Feb 23, 2018

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