I found the derivative of the function: y' = \( 3 \sqrt{x} \over 2x \)-1
Then I plugged in 4, and I got -1/4. Is that correct?
y = 3(x)^(1/2) - x
y' = (3/2)x^(-1/2) - 1
So..... the slope at x = 4 = (3/2) (4)^(-1/2) - 1 = (3/2) / √4 - 1 = (3/4) - 1 = -1/4
Correct !!!
Beautiful explanation, CPhill! I like it!
Thanks, tertre !!!
CPhill always got the best explanation!
Just wanted to thank you for all your help. :)
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