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Assuming x, y, and z are positive real numbers satisfying:

\begin{align*}
xy-z&=15, \\
xz-y&=0, \text{ and} \\
yz-x&=0,
\end{align*}

then, what is the value of $xyz$?

 Mar 9, 2021
 #1
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xyz works out to 1.

 Mar 9, 2021

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