+0  
 
+1
458
1
avatar+206 

Assuming x, y, and z are positive real numbers satisfying:

\begin{align*}
xy-z&=15, \\
xz-y&=0, \text{ and} \\
yz-x&=0,
\end{align*}

then, what is the value of $xyz$?

 Mar 9, 2021
 #1
avatar
0

xyz works out to 1.

 Mar 9, 2021

2 Online Users

avatar
avatar