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avatar+337 

Let $x, y, z$ be real numbers so that

\begin{align*}
y+z & = 13, \\
z+x & = 14, \\
x+y & = 15.
\end{align*}

Find $\sqrt{xyz(x+y+z)}$.

 Mar 19, 2021
 #1
avatar+97 
+1

Hey bestie it's me 

I got 84 because I found that x=8, y=7, and z=6.

 Mar 19, 2021

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