a triangle has a perimeter of 7x-2y+15 and has sides of length 5x+y and 7+x what is the length of the third side
[7x-2y+15] - [(5x+y) + (7+x)]=
Simplify the following:
7 x-2 y+15-((5 x+y)+(x+7))
-(7+6 x+y) = -7-6 x-y:
7 x-2 y+15+-7-6 x-y
Grouping like terms, 7 x-2 y+15-7-6 x-y = (-2 y-y)+(7 x-6 x)+(15-7):
(-2 y-y)+(7 x-6 x)+(15-7)
-2 y-y = -3 y:
-3 y+(7 x-6 x)+(15-7)
7 x-6 x = x:
-3 y+x+(15-7)
15-7 = 8:
Answer: | -3y + x + 8
