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# coefficient

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Find the coefficient of \$u^2 v^9\$ in the expansion of \$(2u - 3v^3 + v^2 - 5u^2 + 1)^5.\$

Jun 27, 2023

#1
+131
+1

We use the Binomial Theorem to expand the given expression. We have:

(2u - 3v + u^2 - v^2)^9 = ∑(k=0 to 9) C(9,k)(2u)^(9-k)(-3v)^k(u^2 - v^2)^(9-k)

To find the coefficient of u^2 v^9, we need to choose k such that (9-k) powers of (u^2 - v^2) multiply out to u^2 and k powers of (-3v) multiply out to v^9. From the first term (2u)^(9-k), we need to choose two powers of u to multiply out to u^2. Therefore, we choose (9-k-2) = (7-k) of the remaining terms to be (u^2 - v^2), and the remaining k terms to be (-3v). This gives us the equation:

2^(9-k) * (-3)^k * C(9,k) * (u^2 - v^2)^(7-k) * (-3v)^k = u^2 v^9 * coefficient

We need to find the value of the coefficient that satisfies this equation. Plugging in u^2 = v^9 = 1, we get:

2^(9-k) * (-3)^k * C(9,k) * (-3)^(k) = coefficient

Simplifying, we get:

coefficient = 2^(9-k) * 3^(2k) * C(9,k)

To find the coefficient of u^2 v^9, we need to find k such that (9-k-2) = (7-k) powers of (u^2 - v^2) multiply out to u^2, and k powers of (-3v) multiply out to v^9. This means that:

7 - k = 2
k = 5

Therefore, the coefficient of u^2 v^9 is:

2^(9-5) * 3^(2*5) * C(9,5) = 2^4 * 3^10 * 126 = 2,176,782,080

Therefore, the coefficient of u^2 v^9 in the expansion of (2u - 3v + u^2 - v^2)^9 is 2,176,782,080.

Jun 27, 2023
#2
+274
+1

I got 1920 @SportzGuy2310 when I expanded it using the binomial theorem.

Jun 27, 2023
#3
0

1920 is the correct coefficient.

Guest Jun 27, 2023
#4
+131
0

Oh sorry, I thought it was to the 9th power

SportzGuy2310  Jun 27, 2023