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A boy has 5-dollar coins and a 10-dollar coins. They are eight coins all together and their value is 55 dollars.  How many of each kind does he have​?

 Mar 16, 2021
 #1
avatar+73 
+1

let's define some variables: x and y, for the 5-dollar coins and the 10-dollar coins, respectively.

 

now let's create a system of equations -

 

x + y = 8

5x + 10y = 55.

 

we can simplify that second equation by dividing both sides by 5. now we get:

 

x + y = 8

x + 2y = 11

 

let's use elimination and subtract these two equations.

 

subtracting, we get y = 3.

 

now to solve for the amount of 5-dollar coins there are, we can plug in our value of y in one of the equations.

 

x + 3 = 8

x = 8 - 3

x = 5.

 

hope this helped! please let me know if you are confused about anything i did :)

 Mar 16, 2021
edited by euph0ria  Mar 16, 2021
 #2
avatar+2135 
0

Hello!

 

Welcome to this forum. :)))

Thanks for the answer. 

I love your username. 

 

=^._.^=

catmg  Mar 16, 2021
 #3
avatar+73 
+1

hello, thank you for the welcome! i've been looking around and this seems like a great place!

 

of course! its my pleasure :)

 

thank you! i love yours too! laugh

euph0ria  Mar 16, 2021
edited by euph0ria  Mar 16, 2021
 #4
avatar+121006 
+2

Yep...welcome , euph0ria....I like  your user name, too!!!!

 

 

 

cool cool cool

CPhill  Mar 16, 2021

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