A combination lock uses three integers in the combination, and the dial is numbered with the integers 0, 1, 2, and 3. If the consecutive numbers in the combination cannot be the same, how many possible combinations are there?
It doesn't seem to be 24
4 possibilities for psition 1 x
3 possibilities for position 2 x
3 possibilities for position 3 = 4 x 3 x 3 = 36 combos
4 possibilities for psition 1 x
3 possibilities for position 2 x
3 possibilities for position 3 = 4 x 3 x 3 = 36 combos