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A combination lock uses three integers in the combination, and the dial is numbered with the integers 0, 1, 2, and 3. If the consecutive numbers in the combination cannot be the same, how many possible combinations are there?

 

 

 

It doesn't seem to be 24

 Feb 22, 2019

Best Answer 

 #1
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4  possibilities for psition 1  x

3 possibilities for position 2   x

3 possibilities for position 3        =   4 x 3 x 3 = 36 combos

 Feb 22, 2019
 #1
avatar+36915 
0
Best Answer

4  possibilities for psition 1  x

3 possibilities for position 2   x

3 possibilities for position 3        =   4 x 3 x 3 = 36 combos

ElectricPavlov Feb 22, 2019

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