In how many ways can 4 balls be placed in 4 boxes if neither the balls nor the boxes are distinguishable?
Really got no idea on how approach.
Just count em...
4 - 0 - 0 - 0
3 - 1 - 0 - 0
2 - 2 - 0 - 0
2 - 1 - 1 - 0
1 - 1 - 1 - 1
So \(\color{brown}\boxed{5}\) ways