+0

# Combinatorics

+1
90
2
+13

If I choose four cards from a standard $52$-card deck, with replacement, what is the probability that I will end up with one card from each suit?

Oct 15, 2020

### 2+0 Answers

#1
+112026
+3

I think.

$$\text{P(each suit different)}=1* \frac{39*26*13}{52*52*52}\\ \text{P(each suit different)}= \frac{3}{4*2*4}\\ \text{P(each suit different)}= \frac{3}{32}\\$$

Oct 15, 2020
#2
+13
0

Correct

MathBoyFarcastik  Oct 15, 2020