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If I choose four cards from a standard $52$-card deck, with replacement, what is the probability that I will end up with one card from each suit?

 Oct 15, 2020

2+1 Answers

 #1
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I think.

 

P(each suit different)=1∗39∗26∗1352∗52∗52P(each suit different)=34∗2∗4P(each suit different)=332

 Oct 15, 2020
 #2
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0

Correctlaugh

MathBoyFarcastik  Oct 15, 2020

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