+0  
 
0
35
2
avatar+11 

If I choose four cards from a standard $52$-card deck, with replacement, what is the probability that I will end up with one card from each suit?

 Oct 15, 2020
 #1
avatar+111124 
+2

I think.

 

\(\text{P(each suit different)}=1* \frac{39*26*13}{52*52*52}\\ \text{P(each suit different)}= \frac{3}{4*2*4}\\ \text{P(each suit different)}= \frac{3}{32}\\ \)

 
 Oct 15, 2020
 #2
avatar+11 
0

Correctlaugh

 
MathBoyFarcastik  Oct 15, 2020

41 Online Users

avatar