If I choose four cards from a standard $52$-card deck, with replacement, what is the probability that I will end up with one card from each suit?
I think.
\(\text{P(each suit different)}=1* \frac{39*26*13}{52*52*52}\\ \text{P(each suit different)}= \frac{3}{4*2*4}\\ \text{P(each suit different)}= \frac{3}{32}\\ \)
Correct
+13 
